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DEBBEI DEBS
10-09-2001, 10:44 AM
:rolleyes:
Hi ya EVERY BODY.

The equipment has been set up to compare the physical interactions of two
sound waves at different freq.: Two generators (A+B) are fed to both an
oscilloscope and a loud speaker via switch box enabling each to be viewed and
heard either separately or combined.


AMPLIFIER OSCILLOSCOPE A B
[ [ [ \ /
[ [ [_____________[ ] wall
[ [_________________________________[ ] (suppose to be box)
[__________________________//
//
( I tried to above to draw a diagram, to see if it would help any one better
- I know not very good, but at least I tried) WEEEEE! Don't give up my
studies for Art drawing HE HE

DOES ANY ONE KNOW HOW TO WORK OUT THE CALCULATIONS FOR:

The period output A as shown on the Oscillator is: 10 ms (milli seconds or
metres per seconds)?

The period output B as shown on Oscillator is: 0.1ms

I need to calculate the output freq. for each tone generator and the
resultant waveform of each sound wave at room temp?

0.1 ms I think is 0.010s? I know anything with nought on left from decimal
point. Oh I'm getting confused. Does any one know how to do this calculation?
If so can you explain it to me.

DAS
10-09-2001, 03:46 PM
I'm trying, but I just can't make out what you are trying to do or exactly what you want to calculate. Maybe someone can explain it to me. I think I have the tools to help, but I don't understand the question.

DEBBEI DEBS
10-09-2001, 04:37 PM
I have equipment set up to compare the physical interactions of two sound waves at different freq. Two tone generators (A + B) are fed to both an oscilloscope and a loud speaker via a switch box enabling each to be viewed and heard either separaetely or combined.

The period of output A is shown on oscillaotr is: 10ms
The period of output B is shown on oscillator is: 0.1ms

Calculate the output frequency for each tone generator and the resultant wavelength of each sound wave at room temperature. I have to show how the calcualtion is done from benin to end.

I hope that this is understandable. Any one with Acoustic knowledge should understnad. I only have 12 hours of learning this subject.

Hope u can help me.

Thank you.

love Debbie debs xxx:rolleyes: :confused: :confused:

DAS
10-09-2001, 05:03 PM
Okay, I think I have the gist of it now.


I'll avoid doing it all for you (hey, you're supposed to be learning here, right?), but I think I can shed some light on the subject.


If a repeating waveform has a period of 10ms, then you know it repeats once every 10ms. This means in 100ms it repeats 10 times. And in 1000 ms it repeats 100 times. 1000ms is the same as one second, so you know it repeats 100 times per second. This is the same thing as saying it is 100 Hz. The frequency is 100 Hz, or 100 repetitions per second.

Next it is important to know that wavelength and frequency are inversely related to each other. The higher the frequency (more repetitions) the shorter the wavelength. There is a simple formula to calculate this.


W = C/F, where:

W is the wavelength, C is a constant (in this case the speed of sound in air - usually considered to be 1132 feet per second, but you should go by what your book says - I presume it's in meters), and F is frequency in Hz.

So lets plug in the numbers to find the wavelength of that 100 Hz output.

W = 1132/100

So we see that the wavelength is 11.32 feet.

This should be enough to get you rolling. Good luck.

DEBBEI DEBS
10-09-2001, 05:31 PM
Thank you Das :D

That will get me started. Thank you (KISS) I just sent you a big kiss. This subject is so hard, but i get there, I know I will.

Do you know any sites that would be good for me?

Hope you have a lovely day tomorrow and if you need a friend to talk to any time. Just email me and I be here.

Love

Debbie x